Valid Number
描述
Validate if a given string is numeric.
Some examples:
"0" => true
" 0.1 " => true
"abc" => false
"1 a" => false
"2e10" => true
Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.
分析
细节实现题。
本题的功能与标准库中的strtod()
功能类似。
有限自动机
// Valid Number
// @author 龚陆安 (http://weibo.com/luangong)
// finite automata,时间复杂度O(n),空间复杂度O(n)
class Solution {
public:
bool isNumber(const string& s) {
enum InputType {
INVALID, // 0
SPACE, // 1
SIGN, // 2
DIGIT, // 3
DOT, // 4
EXPONENT, // 5
NUM_INPUTS // 6
};
const int transitionTable[][NUM_INPUTS] = {
-1, 0, 3, 1, 2, -1, // next states for state 0
-1, 8, -1, 1, 4, 5, // next states for state 1
-1, -1, -1, 4, -1, -1, // next states for state 2
-1, -1, -1, 1, 2, -1, // next states for state 3
-1, 8, -1, 4, -1, 5, // next states for state 4
-1, -1, 6, 7, -1, -1, // next states for state 5
-1, -1, -1, 7, -1, -1, // next states for state 6
-1, 8, -1, 7, -1, -1, // next states for state 7
-1, 8, -1, -1, -1, -1, // next states for state 8
};
int state = 0;
for (auto ch : s) {
InputType inputType = INVALID;
if (isspace(ch))
inputType = SPACE;
else if (ch == '+' || ch == '-')
inputType = SIGN;
else if (isdigit(ch))
inputType = DIGIT;
else if (ch == '.')
inputType = DOT;
else if (ch == 'e' || ch == 'E')
inputType = EXPONENT;
// Get next state from current state and input symbol
state = transitionTable[state][inputType];
// Invalid input
if (state == -1) return false;
}
// If the current state belongs to one of the accepting (final) states,
// then the number is valid
return state == 1 || state == 4 || state == 7 || state == 8;
}
};